Решение задачи #59410
Решить неравенство 4cos²х <= 3
4cos2х <= 3
cos2х <= 3/4
|cosx| <= √000;">3/2
| [ | cosx <= √3/2 |
| cosx >= -√3/2 |
| [ | x <= π/6 + πk и x >= -5π/6 + πk |
| x <= 5π/6 + πk и x >= -π/6 + πk |
Решение других задач:
4cos2х <= 3
cos2х <= 3/4
|cosx| <= √000;">3/2
| [ | cosx <= √3/2 |
| cosx >= -√3/2 |
| [ | x <= π/6 + πk и x >= -5π/6 + πk |
| x <= 5π/6 + πk и x >= -π/6 + πk |
Решение других задач: