Решение задачи #62050
(1-2c)²-4c(c+1)
(1-2c)2 - 4c(c+1) = (1-2c)2 - 4c2 - 4c = (1-2c)2 - (1 + 4c + 4c2) + 1 = (1-2c)2 - (1+2c)2 + 1 = (1 - 2c - 1 - 2c)(1 - 2c + 1 + 2c) + 1 = 1 - 8c2 = (1 - 2√000;">2c)(1 + 2√2c)
Теги задачи:
(1-2c)2 - 4c(c+1) = (1-2c)2 - 4c2 - 4c = (1-2c)2 - (1 + 4c + 4c2) + 1 = (1-2c)2 - (1+2c)2 + 1 = (1 - 2c - 1 - 2c)(1 - 2c + 1 + 2c) + 1 = 1 - 8c2 = (1 - 2√000;">2c)(1 + 2√2c)
Теги задачи: